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30x-12-5x^2=0
a = -5; b = 30; c = -12;
Δ = b2-4ac
Δ = 302-4·(-5)·(-12)
Δ = 660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{660}=\sqrt{4*165}=\sqrt{4}*\sqrt{165}=2\sqrt{165}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{165}}{2*-5}=\frac{-30-2\sqrt{165}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{165}}{2*-5}=\frac{-30+2\sqrt{165}}{-10} $
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